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LG Vu 3 to launch in October, new QuickView cases teased

17 September, 2013 | Read the news | Post your comment
LG Vu 3 to launch in October, new QuickView cases teased - read the full textAccording to Korean media outlet etnews, LG is preparing to launch the Vu 3 in October as a direct rival to the Samsung Galaxy Note 3. In addition, LG has teased a couple of specially made cases for the phone hinting its almost ready for prime time. The LG Vu 3 is said to be cheaper than its...


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I got the LG L9 first and then I got the Vu 2 which is a stretched version of L9.

I don't know why but for some Reason, I'm loving the Vu 2 the same with the L9.

When you have the Vu 2 or any Vu phone, you'll know what I'm saying.

  • Reply
  • 2013-12-20 13:02
  • w0Pt

So LG didnít cancel its Vu series. Maybe there is still a market after all for phones with screens that has 4:3 aspect ratio. It maybe short & stout but the 4:3 aspect ratio is actually better for reading ebooks and web browsing.

Will definitely consider this as my next phablet.

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  • 2013-09-24 08:05
  • YT@8

vu fans and LG should start a vu website once you buy you understand have vu iii global

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  • 2013-09-19 20:31
  • Sbcq

i love my vu iam waiting for global launch i dont get the haters

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  • 2013-09-19 20:26
  • Sbcq

best phone for books lover
i love my p895, sharp screen, very easy to read at 4:3 ratio.
i hope vu3 comes with sdcard slot
manga lover and comic lover,this is the best phone for them.
every japanese otaku will go for vu3

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  • 2013-09-18 06:44
  • y$ft

Why 4:3? It's so difficult to grip.

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  • 2013-09-18 03:07
  • F%Q5

So this is the competitor of Note 3 and Z Ultra.. A little too late i think..

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  • 2013-09-18 02:54
  • Kg6y

> In reply to Anonymous @ 2013-09-17 14:02 from pF7r - click to readI don't know there was vu 2.. All i know is just vu 1.. Hehe

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  • 2013-09-18 02:46
  • Kg6y

> In reply to yeip @ 2013-09-17 15:37 from N9xA - click to reada=45deg:
here's the proof:
from sin(a)*cos(a),
this ia a half-angle formula equal to:
0.5sin(2a)=sin(a)*cos(a), or
for maximum area, derivative of the function below must be equal to zero:
A = x*y = (d^2)*sin(a)*cos(a)
A = x*y = (d^2)*0.5sin(2a)
dA/da = (d^2)*0.5cos(2a) =0

2nd proof:
Using Pythagorean Theorem:
y=x(d^2-x^2)^0.5, then

x=y to obtain maximum area:

  • Reply
  • 2013-09-17 22:22
  • Ui%E

4.3 aspect ratio is marvellous for me! Waiting for this VU3 to replace my P895 that Im currently using now

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  • 2013-09-17 18:34
  • K1B7

is 4:3 compatible with all the apps? if it is then i'm the 4:3 aspect ratio...

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  • 2013-09-17 17:51
  • K7et

> In reply to wardroid @ 2013-09-17 15:21 from 0IFR - click to readlg vu series was already sold over 2 millions in south korea alone.

maybe sounds not good for you , but good for others..
( koreans)

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  • 2013-09-17 17:28
  • uSSL

come on lg get x-series back on line!

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  • 2013-09-17 16:09
  • pT2T

> In reply to Joven @ 2013-09-17 14:53 from ncx@ - click to readThe long explanation:
Any given rectangle with sides "x" and "y" and diagonal "d", have an "a" angle (a portion of the full 90° angle next to the diagonal) so that:
sen(a) = x/d => x = d*sin(a) [i]
cos(a) = y/d => y = d*cos(a) [ii]

As the area of that rectangle would be simply x*y, the area becomes
A = x*y = (d^2)*sin(a)*cos(a) (because of i and ii)

To get the maximum area you perform
max [A] = max [(d^2)*sin(a)*cos(a)]
Because (d^2) is always positive and independant from the angle "a" in this model,
max [A] = (d^2)max[sin(a)*cos(a)]

And you can find that the angle "a" that maximizes sin(a)*cos(a) is 45° or (pi/4) rad. I won't proof this but here's a Wolfram Alpha link*cos(a))

And the only rectangle sporting a 45° semiangle next to it's diagonal is a square. And this is why the squarish the rectangle, the biggest the area is, given it has the same diagonal length than other rectangle.

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  • 2013-09-17 15:37
  • N9xA

Still working for VU?

Hopeless effort!

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  • 2013-09-17 15:21
  • 0IFR

> In reply to Joven @ 2013-09-17 14:53 from ncx@ - click to readNo, he's right. The 5'' are the diagonal (corner to corner) measure of the screen. Given a diagonal, the squarish the shape is, the bigger the area. In faqct, given a fixed diagonal, the largest "rectangle" you can have around it in terms of area is a square. So Squarish is indeed bigger.

  • Reply
  • 2013-09-17 15:18
  • N9xA

> In reply to beckon @ 2013-09-17 14:28 from UD%n - click to readNo, definitely stylish !

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  • 2013-09-17 15:01
  • M$xv

> In reply to Lenny @ 2013-09-17 14:24 from 4QpC - click to readMany of people interested in mobile devices except you...

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  • 2013-09-17 14:59
  • M$xv

> In reply to Iskander @ 2013-09-17 14:19 from mA51 - click to readI don't see your point. Still 5" area, doesn't matter aspect ratio

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  • 2013-09-17 14:53
  • ncx@

> In reply to beckon @ 2013-09-17 14:28 from UD%n - click to readLOL. agree.

  • Reply
  • 2013-09-17 14:51
  • URH{

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