# LG Vu 3 to launch in October, new QuickView cases teased

- VuTers
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I got the LG L9 first and then I got the Vu 2 which is a stretched version of L9.

I don't know why but for some Reason, I'm loving the Vu 2 the same with the L9.

When you have the Vu 2 or any Vu phone, you'll know what I'm saying.

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- 2013-12-20 13:02
- w0Pt

**Milhouse**- Report
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So LG didn’t cancel its Vu series. Maybe there is still a market after all for phones with screens that has 4:3 aspect ratio. It maybe short & stout but the 4:3 aspect ratio is actually better for reading ebooks and web browsing.

Will definitely consider this as my next phablet.

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- 2013-09-24 08:05
- YT@8

- jray
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vu fans and LG should start a vu website once you buy you understand have vu iii global

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- 2013-09-19 20:31
- Sbcq

- jray
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i love my vu iam waiting for global launch i dont get the haters

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- 2013-09-19 20:26
- Sbcq

- goron
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best phone for books lover

i love my p895, sharp screen, very easy to read at 4:3 ratio.

i hope vu3 comes with sdcard slot

manga lover and comic lover,this is the best phone for them.

every japanese otaku will go for vu3

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- 2013-09-18 06:44
- y$ft

**Jati Royat**- Report
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So this is the competitor of Note 3 and Z Ultra.. A little too late i think..

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- 2013-09-18 02:54
- Kg6y

**Jati Royat**- Report
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> In reply to Anonymous @ 2013-09-17 14:02 from pF7r - click to readI don't know there was vu 2.. All i know is just vu 1.. Hehe

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- 2013-09-18 02:46
- Kg6y

**junay**- Report
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> In reply to yeip @ 2013-09-17 15:37 from N9xA - click to reada=45deg:

here's the proof:

from sin(a)*cos(a),

this ia a half-angle formula equal to:

0.5sin(2a)=sin(a)*cos(a), or

sin2a=2sin(a)*cos(a)

d/da[sin(2a)]=2cos(2a)

for maximum area, derivative of the function below must be equal to zero:

A = x*y = (d^2)*sin(a)*cos(a)

A = x*y = (d^2)*0.5sin(2a)

dA/da = (d^2)*0.5cos(2a) =0

cos(2a)=90deg

2a=90

a=45deg

2nd proof:

A=xy

Using Pythagorean Theorem:

d^2=x^2+y^2

y=(d^2-x^2)^0.5

y=x(d^2-x^2)^0.5, then

A=((dx)^2-x^4)^0.5

Amax:

A'=0

0=0.5((dx)^2-x^4)^(-0.5)(2dx-4x^3)

0=d-2x^2

x=d/2^0.5

y=(d^2-x^2)^0.5

=(d^2-(d/2^0.5)^2)^0.5

=(d^2-d^2/2)^).5

=d/2^0.5

therefore:

x=y to obtain maximum area:

Amax=xy=(d/2^0.5)(d/2^0.5)=d^2/2

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- 2013-09-17 22:22
- Ui%E

- Haissac
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4.3 aspect ratio is marvellous for me! Waiting for this VU3 to replace my P895 that Im currently using now

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- 2013-09-17 18:34
- K1B7

**wis**- Report
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is 4:3 compatible with all the apps? if it is then i'm sold...love the 4:3 aspect ratio...

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- 2013-09-17 17:51
- K7et

- Anonymous
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> In reply to wardroid @ 2013-09-17 15:21 from 0IFR - click to readlg vu series was already sold over 2 millions in south korea alone.

maybe sounds not good for you , but good for others..

( koreans)

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- 2013-09-17 17:28
- uSSL

- yeip
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> In reply to Joven @ 2013-09-17 14:53 from ncx@ - click to readThe long explanation:

Any given rectangle with sides "x" and "y" and diagonal "d", have an "a" angle (a portion of the full 90° angle next to the diagonal) so that:

sen(a) = x/d => x = d*sin(a) [i]

cos(a) = y/d => y = d*cos(a) [ii]

As the area of that rectangle would be simply x*y, the area becomes

A = x*y = (d^2)*sin(a)*cos(a) (because of i and ii)

To get the maximum area you perform

max [A] = max [(d^2)*sin(a)*cos(a)]

Because (d^2) is always positive and independant from the angle "a" in this model,

max [A] = (d^2)max[sin(a)*cos(a)]

And you can find that the angle "a" that maximizes sin(a)*cos(a) is 45° or (pi/4) rad. I won't proof this but here's a Wolfram Alpha link

http://www.wolframalpha.com/in...n(a)*cos(a))

And the only rectangle sporting a 45° semiangle next to it's diagonal is a square. And this is why the squarish the rectangle, the biggest the area is, given it has the same diagonal length than other rectangle.

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- 2013-09-17 15:37
- N9xA

- yeipr
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> In reply to Joven @ 2013-09-17 14:53 from ncx@ - click to readNo, he's right. The 5'' are the diagonal (corner to corner) measure of the screen. Given a diagonal, the squarish the shape is, the bigger the area. In faqct, given a fixed diagonal, the largest "rectangle" you can have around it in terms of area is a square. So Squarish is indeed bigger.

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- 2013-09-17 15:18
- N9xA

**ardaolgac**- Report
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> In reply to beckon @ 2013-09-17 14:28 from UD%n - click to readNo, definitely stylish !

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- 2013-09-17 15:01
- M$xv

**ardaolgac**- Report
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> In reply to Lenny @ 2013-09-17 14:24 from 4QpC - click to readMany of people interested in mobile devices except you...

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- 2013-09-17 14:59
- M$xv

- Joven
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> In reply to Iskander @ 2013-09-17 14:19 from mA51 - click to readI don't see your point. Still 5" area, doesn't matter aspect ratio

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- 2013-09-17 14:53
- ncx@

**slazher**- Report
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> In reply to beckon @ 2013-09-17 14:28 from UD%n - click to readLOL. agree.

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- 2013-09-17 14:51
- URH{

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