I got the LG L9 first and then I got the Vu 2 which is a stretched version of L9.
I don't know why but for some Reason, I'm loving the Vu 2 the same with the L9.
When you have the Vu 2 or any Vu phone, you'll know what I'm saying.
So LG didn’t cancel its Vu series. Maybe there is still a market after all for phones with screens that has 4:3 aspect ratio. It maybe short & stout but the 4:3 aspect ratio is actually better for reading ebooks and web browsing.
Will definitely consider this as my next phablet.
vu fans and LG should start a vu website once you buy you understand have vu iii global
best phone for books lover
i love my p895, sharp screen, very easy to read at 4:3 ratio.
i hope vu3 comes with sdcard slot
manga lover and comic lover,this is the best phone for them.
every japanese otaku will go for vu3
So this is the competitor of Note 3 and Z Ultra.. A little too late i think..
Anonymous, 17 Sep 2013How many people bought Vu 2?I don't know there was vu 2.. All i know is just vu 1.. Hehe
yeip, 17 Sep 2013The long explanation:
Any given rectangle with sides "x" and "y" and diag... morea=45deg:
here's the proof:
this ia a half-angle formula equal to:
for maximum area, derivative of the function below must be equal to zero:
A = x*y = (d^2)*sin(a)*cos(a)
A = x*y = (d^2)*0.5sin(2a)
dA/da = (d^2)*0.5cos(2a) =0
Using Pythagorean Theorem:
x=y to obtain maximum area:
4.3 aspect ratio is marvellous for me! Waiting for this VU3 to replace my P895 that Im currently using now
is 4:3 compatible with all the apps? if it is then i'm sold...love the 4:3 aspect ratio...
wardroid, 17 Sep 2013Still working for VU?
lg vu series was already sold over 2 millions in south korea alone.
maybe sounds not good for you , but good for others..
Joven, 17 Sep 2013I don't see your point. Still 5" area, doesn't matter aspect ratioThe long explanation:
Any given rectangle with sides "x" and "y" and diagonal "d", have an "a" angle (a portion of the full 90° angle next to the diagonal) so that:
sen(a) = x/d => x = d*sin(a) [i]
cos(a) = y/d => y = d*cos(a) [ii]
As the area of that rectangle would be simply x*y, the area becomes
A = x*y = (d^2)*sin(a)*cos(a) (because of i and ii)
To get the maximum area you perform
max [A] = max [(d^2)*sin(a)*cos(a)]
Because (d^2) is always positive and independant from the angle "a" in this model,
max [A] = (d^2)max[sin(a)*cos(a)]
And you can find that the angle "a" that maximizes sin(a)*cos(a) is 45° or (pi/4) rad. I won't proof this but here's a Wolfram Alpha link
And the only rectangle sporting a 45° semiangle next to it's diagonal is a square. And this is why the squarish the rectangle, the biggest the area is, given it has the same diagonal length than other rectangle.
Joven, 17 Sep 2013I don't see your point. Still 5" area, doesn't matter aspect ratioNo, he's right. The 5'' are the diagonal (corner to corner) measure of the screen. Given a diagonal, the squarish the shape is, the bigger the area. In faqct, given a fixed diagonal, the largest "rectangle" you can have around it in terms of area is a square. So Squarish is indeed bigger.
beckon, 17 Sep 2013Stupid looking phone from LGNo, definitely stylish !
Lenny, 17 Sep 2013How many people knew there was a Vu 1? Many of people interested in mobile devices except you...